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Quiz Solution for Math 1321 - Quiz 3 - Problem 1 and 2, Quizzes of Trigonometry

The solutions for problem 1 and 2 of quiz 3 in math 1321. Problem 1 involves computing the exact value of an expression using trigonometric identities, while problem 2 is about identifying the truth or falsehood of a trigonometric equation and providing reasons. No calculator is allowed.

Typology: Quizzes

Pre 2010

Uploaded on 03/11/2009

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Download Quiz Solution for Math 1321 - Quiz 3 - Problem 1 and 2 and more Quizzes Trigonometry in PDF only on Docsity! Math 1321 Quiz 3 Name: September 11, 2002 Instructions: 1. Be sure to show all your work, NO WORK = NO CREDIT!! 2. Read all questions carefully and be sure to give the result wanted. 3. Box in or highlight your final answer. NO BOX = NO CREDIT 1. Exercise 1.7, Problem 8: Compute the exact value of the following expression. DO NOT USE A CALCULATOR. 3 cos4 30o โˆ’ 5 sin3 30o โˆ’ sin2 45o โˆ’ sin 90o Solution: 3 cos4 30o โˆ’ 5 sin3 30o โˆ’ sin2 45o โˆ’ sin 90o =3(cos 30o)4 โˆ’ 5(sin 30o)3 โˆ’ (sin 45o)2 โˆ’ (sin 90o) =3 (โˆš 3 2 )4 โˆ’ 5 ( 1 2 )3 โˆ’ (โˆš 2 2 )2 โˆ’ (1) =3 ( 9 16 ) โˆ’ 5 ( 1 8 ) โˆ’ ( 1 2 ) โˆ’ (1) = ( 27 16 ) โˆ’ ( 10 16 ) โˆ’ ( 8 16 ) โˆ’ ( 16 16 ) =โˆ’ 7 16 2. Identify as true or false and GIVE REASONS. DO NOT USE A CALCULATOR. cos 30o + cos 60o = cos 90o Solution: Well cos 30o = โˆš 3 2 and cos 60o = 1 2 so cos 30o + cos 60o = โˆš 3 2 + 1 2 6= 0 = cos 90o 1
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